base 10 logarithm造句
例句与造句
- where the base 10 logarithm has been used in the final answer for ease of calculation.
- And of course we like base 10 logarithms : 1, 10, 100, 1000.
- This is 20 times the base 10 logarithm of the ratio of a given root-mean-square sound pressure to the reference sound pressure.
- The base 10 logarithm is taken of this function, and a first order linear regression, linear fit, is performed on the resulting data set, that is
- The DIN system was inspired by Scheiner's system, but the sensitivities were represented as the base 10 logarithm of the sensitivity multiplied by 10, similar to decibels.
- It's difficult to find base 10 logarithm in a sentence. 用base 10 logarithm造句挺难的
- For converting to and from base 10 logarithms and natural logarithms the natural logarithm of 10 ( 2.30259 ) and e ( 2.71828 ) are printed on the case.
- It is approximately the negative of the base 10 logarithm of the molar concentration, measured in units of Pure water is neutral, at pH 7, being neither an acid nor a base.
- Thus an increase of 20?( and not 19?as in Scheiner's system ) represented a hundredfold increase in sensitivity, and a difference of 3?was much closer to the base 10 logarithm of 2 ( 0.30103 & ):
- The Nernst equation is frequently expressed in terms of base 10 logarithms ( " i . e . ", common logarithms ) rather than natural logarithms, in which case it is written, " for a cell at 25 癈 ":
- Formally, " L AT " is 10 times the base 10 logarithm of the ratio of a root-mean-square A-weighted sound pressure during a stated time interval to the reference sound pressure and there is no time constant involved.
- Originally the sensitivity was written as a fraction with'tenths'( for example " 18 / 10?DIN " ), where the resultant value 1.8 represented the relative base 10 logarithm of the speed .'Tenths'were later abandoned with DIN 4512 : 1957-11, and the example above would be written as " 18?DIN ".
- Note that the log and exp functions can be used, as in your first equation, in place of the general y ^ x function, so you could write f ( x ) = fStart * 10 ^ ( log ( fEnd / fStart ) * x / steps ), where log is base 10 logarithm or the 10 ^ is replaced with exponentiation of the same base as the log.
